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Friday, October 25, 2013

Indices

SURDS AND INDICES



IMPORTANT FORMULAE


1. LAWS OF INDICES:

(i) am x an = am + n

(ii) am­ / an = am - n

(iii) ( am )n = amn

(iv) ( a b )n = anbn



(v) ( a / b )n = ( an / bn )

(vi) a0 = 1



2. SURDS: Let a be a rational number and n be a positive integer such that a1/n = nsqrt(a)

is irrational. Then nsqrt(a) is called a surd of order n.

3. LAWS OF SURDS:

(i) n√a = a1/2

(ii) n √ab = n √a * n √b

(iii) n √a/b = n √a / n √b

(iv) (n √a)n = a

(v) m√(n√(a)) = mn√(a)

(vi) (n√a)m = n√am

Examples:

Ex. 1. Simplify : (i) (27)2/3 (ii) (1024)-4/5 (iii)( 8 / 125 )-4/3

Sol . (i) (27)2/3 = (33)2/3 = 3( 3 * ( 2/ 3)) = 32 = 9

(ii) (1024)-4/5 = (45)-4/5 = 4 { 5 * ( (-4) / 5 )} = 4-4 = 1 / 44 = 1 / 256

(iii) ( 8 / 125 )-4/3 = {(2/5)3}-4/3 = (2/5){ 3 * ( -4/3)} = ( 2 / 5 )-4 = ( 5 / 2 )4 = 54 / 24

Ex. 2. Evaluate: (i) (.00032)3/5 (ii)l (256)0.16 x (16)0.18.
Sol. (i) (0.00032)3/5 = ( 32 / 100000 )3/5. = (25 / 105)3/5 = {( 2 / 10 )5}3/5 = ( 1 / 5 )(5 * 3 / 5) = (1/5)3 = 1 / 125

(ii) (256)0. 16 * (16)0. 18 = {(16)2}0. 16 * (16)0. 18 = (16)(2 * 0. 16) * (16)0. 18

=(16)0.32 * (16)0.18 = (16)(0.32+0.18) = (16)0.5 = (16)1/2 = 4.

Ex. 3. Find the largest from among 4√6, √2 and 3√4.

Sol. Given surds are of order 4, 2 and 3 respectively. Their L.C,M, is 12, Changing each to a surd of order 12, we get:

4√6 = 61/4 = 6((1/4)*(3/3)) = 63/12 = (63)1/12 = (216)1/12.

√2 = 21/2 = 2((1/2)*(6/6)) = 26/12 = (26)1/12 = (64)1/12.

3√4 = 41/3 = 4((1/3)*(4/4)) = 44/12 = (44)1/12 = (256)1/12.

Clearly, (256)1/12 > (216)1/12 > (64)1/12

Largest one is (256)1/12. i.e. 3√4 .

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